Question

The hot resistance of 240V filament lamp is 960Ω. Find the power and current.

Answer 1

$\sf{\large{\underline{\underline{EXPLANATION:}}}}$

$\sf{Given}\begin{cases}\sf{V=240v}\\ \sf{R=960Ω}\\ \sf{P=??}\\ \sf{I=??}\end{cases}$

$\textbf{\underline{By using formula,,}}</p><p>$

$\sf{\boxed{P=\frac{V^{2}}{R}}}$

$\sf{\implies{P=\frac{(240)^{2}}{960}}}$

$\sf{\implies{P=\cancel\dfrac{57600}{960}}}$

$\sf{\implies{P=60W}}$

$\textbf{\underline{Thus,,}}</p><p>$

$\sf{\boxed{P=I^{2}R}}$

$\sf{\implies{60=960I^{2}}}$

$\sf{\implies{\frac{60}{960}=I^{2}}}$

$\sf{\implies{\sqrt{\cancel\dfrac{6}{96}}=I}}$

$\sf{\implies{\sqrt\frac{1}{16}=I}}$

$\sf{\implies{\frac{1}{4}=I}}$

$\sf{\implies{I=0.25A}}$

Therefore,,

• Power,P=60W

• Current,I=0.25A

$\rule{200}2$

❣️❣️★Hope it helps★❣️❣️