Math, asked by SanyamSaini770, 1 year ago

The hour and minute hands of a clock are 4 cm and 6 cm long respectively. Find the sum of distances travelled by their tips in 2 days ?



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Answers

Answered by amitnrw
3

Answer:

13.07 m

Step-by-step explanation:

1 circle = perimeter = 2 * Pie * R

Hour clock in 1 circle = 2 * (22/7)* 4 = 176/7 cm

2 days = 48 hrs = 4 cycle by hour clock  ( as hour clock complete one cycle in 12 hrs)

Distance traveled by Hour clock =  4 * 176/7 = 704/7 cm

Minute clock in 1 circle = 2 * (22/7)* 6 = 264/7 cm

2 days = 48 hrs = 48 cycle by Minute clock  ( as minute cycle cover one circle in 1 hr)

Distance traveled by Minute clock =  48 * 176/7 = 8448/7 cm

Total distance = 704/7 + 8448/7  = 1307.43 cm

= 13.07 m


Answered by Anonymous
3

Answer:

Given :

Length of short hand = 4 cm

Length of long hand = 6 cm

We know short hand make 1 revolution in 12 hours while long hand in 1 hour.

Distance travelled by short hand in 48 hours = 4 × 2 π × 4 = 32 π cm

Distance travelled by long hand in 48 hours = 48 × 2 π × 6 = 576 π cm

Total distance travelled = 32 π cm +  576 π cm = 608 π cm

Therefore ,  sum of distances travelled by their tips in two day is 608 π cm.

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