The hour and minute hands of a clock are4.2 cm and 7cm long respectively.find the sum of the distances covered by their tips in 1 day?
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CIRCUMFERENCE OF HOUR HANDS=2(PIE)R=2x22/7x42/10=264/10
AS HOUR HANDS MAKES 2 ROUNDS IN A DAY,
THEREFORE DISTANCE COVERED BY HOURS HANDS=264x2/10=528/10=52.8CMS
CIRCUMFERENCE OF MINUTE HANDS=2(PIE)R=2x22/7x7=44
AS MINUTE HANDS MAKES 24 ROUNDS IN A DAY,
THEREFORE DISTANCE COVERED BY MINUTE HANDS=44x24=1056 CMS
TOTAL DISTANCE COVERED BY BOTH=52.80+1056=1108.80 CMS
AS HOUR HANDS MAKES 2 ROUNDS IN A DAY,
THEREFORE DISTANCE COVERED BY HOURS HANDS=264x2/10=528/10=52.8CMS
CIRCUMFERENCE OF MINUTE HANDS=2(PIE)R=2x22/7x7=44
AS MINUTE HANDS MAKES 24 ROUNDS IN A DAY,
THEREFORE DISTANCE COVERED BY MINUTE HANDS=44x24=1056 CMS
TOTAL DISTANCE COVERED BY BOTH=52.80+1056=1108.80 CMS
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