The hybridization involved in complex [Ni(CN)₄]²⁻ is
(At. No. Ni = 28) [2015 RS]
(a) dsp² (b) sp³
(c) d²sp² (d) d²sp³
Answers
Answered by
1
Answer:
The hybridization involved in complex [Ni(CN)₄]²⁻ is
(At. No. Ni = 28) [2015 RS]
(a) dsp²
(b) sp³
(c) d²sp²✔
(d) d²sp³
Answered by
0
The hybridization involved in complex [Ni(CN)₄]²⁻ is (a) dsp².
- The outer electronic configuration of Ni 2+ ion is 3D`84S`0
- dsp² is a square planar, while others are octahedral and tetradedral
- One 3d, one 4s, and two 4p orbitals undergo dsp² hybridization.
- Four identical dsp² hybrid orbitals are occupied by four pairs of four cyanide ligands of electrons, thus forming [Ni(CN)₄]²⁻.
Similar questions