Question

the hybridization of a molecule having 16.67 % s character in the hybrid orbital of centre atom will be

a. sp³
b. sp³d
c. sp²
d. sp³d²



plz tell the correct answer from the option only plz​

Answer 1

Explanation:

The given data is summarized in the following table:

Compound:

A

B

C

D

Hybridization:

sp

3

d

sp

3

sp

2

sp

Shape like:

I

3

−

H

2

O H

2

O I

3

−

Number of bonding domains:

2

2

2

2

Number of lone pairs:

3 2 1 0

Since the compound A is sp

3

d

2

hybridised and has only 2 bonding domians, it must have 3 lone pair of electrons. Similarly, B,C and D have 2, 1 and 0 lone pairs of electrons respectively.

Hence, the sum P+Q+R+S=3+2+1+0=6

Answer 2

Answer:

sp^3 I think

.................: )