Question

The hybridizations of atomic orbitals of nitrogen in

Answer 1

Answer:

The nitrogen atom is sp3 hybridized with one hybrid orbital occupied by the lone pair. The molecular structure of water is consistent with a tetrahedral arrangement of two lone pairs and two bonding pairs of electrons

Answer 2

Hard

Answer

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Correct option is

B

sp, sp

2

and sp

3

respectively

Here's a nice short trick.

1) Count and add all the electrons in valence shell

2) Divide it by 8

3) On dividing by 8 you will get a remainder and quotient, add quotient + (remainder / 2)

4) Now get the hybridization corresponding to the number what you got

If 2 its sp,if 3 its sp

2

, if 4 its sp

3

, if 5 its sp

3

d and so on.

Ex: NO

2+

-> Total electrons in valence shell : 5+6×2−1=16.

->16/8=2. Quotient = 2 and Remainder =0

-> 2+0/2=2 i.e sp

NH

4+

-> Total electrons in valence shell : 5+7×4−1=32.

-> 32/8=4. Quotient = 4 and Remainder = 0

-> 4+0/2=4 i.e sp

3

NO

3−

-> Total electrons in valence shell : 5+6×3+1=24.

-> 24/8=3. Quotient = 3 and Remainder = 0

-> 3+0/2=3 i.e sp

2

Hence option B is correct.