Question

The hydrocarbon contains 79. 87% carbon and 20. 13% of hydrogen what is the empirical formula

Answer 1

Answer:CH3

Explanation:

Answer 2

Answer: Empirical formula is $CH_3$.

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 79.87 g

Mass of H = 20.13 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{79.87g}{12g/mole}=6.65moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{20.13g}{1g/mole}=20.13moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =$\frac{6.65}{6.65}=1$

For H=$\frac{20.13}{6.65}=3$

The ratio of C: H= 1: 3

Hence the empirical formula is $CH_3$.