Question

The kinetic energy of a body is increased by 300%. The momentum of the body would increase 4) 300% 1) 50% 2) 100

Answer 1

Answer:

100%

Explanation:

Kinetic Energy = $\frac{mv^{2}}{2}$

which implies the

$KE_{1}=\frac{mv_{1}^{2}}{2}\\KE_{2}=\frac{mv_{2}^{2}}{2}$

It is given that Kinetic energy is increased by 300%

$KE_{2} = KE_{1} + \frac{300}{100}KE_{1}$

$KE_{2} = 4KE_{1}$

which implies that

$\frac{mv_{2}^{2}}{2} = 4*\frac{mv_{1}^{2}}{2}\\\\v_{2}^{2} = 4v_{1}^{2}\\v_{2} = 2v_{1}$

momentum = mv

Initial momentum:

$mv_{1}$

Final momentum :

$mv_{2}$

change in momentum:

$mv_{2} - mv_{1}=2mv_{1}-mv_{1}=mv_{1}$

percentage change :

$=\frac{change}{Initial} *100\\\\=\frac{mv_{1}}{mv_{1}}*100\\=100$

Answer 2

Answer:

100%

Explanation: