the hypotenuse and the base of the triangle are 13 cm and 12 CM respectively find the areas
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hypotenuse=13cm base =12cm
hypotenuse whole sq=1st side sq + 2nd side sq
hypotenuse is given 1side given by this other side mil jaayegi then all 3 sides we have,then by heron's formula hm area nikal sakte h
I hope it helps ...
hypotenuse whole sq=1st side sq + 2nd side sq
hypotenuse is given 1side given by this other side mil jaayegi then all 3 sides we have,then by heron's formula hm area nikal sakte h
I hope it helps ...
shashbhushansingh:
thanx
Answered by
1
Hey...!!,
Hypotenuse = 13 cm
Base = 12 cm
So,
Hypotenuse square = Base square + Height square
13 squares = 12 square + H sq
169 = 144 + H sq
H sq = 169 - 144
H sq = 25
H = 25 under root
H = 5
Height = 5 cm
Base = 12 cm
Area = (1/2 x 12 x 5) cm sq
= 30 cm sq
Hope it helps...!!!
Hypotenuse = 13 cm
Base = 12 cm
So,
Hypotenuse square = Base square + Height square
13 squares = 12 square + H sq
169 = 144 + H sq
H sq = 169 - 144
H sq = 25
H = 25 under root
H = 5
Height = 5 cm
Base = 12 cm
Area = (1/2 x 12 x 5) cm sq
= 30 cm sq
Hope it helps...!!!
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