The hypotenuse of a 45-45-90 triangle has a length of 10 units. what is the length of one of its legs?
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a²+b²= c²
a,b=> legs
c=> hypotenuse
a²+b²= 10²
a²+b²= 100
a²+b²= √100
a,b= 5√2 units
a,b=> legs
c=> hypotenuse
a²+b²= 10²
a²+b²= 100
a²+b²= √100
a,b= 5√2 units
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