THE HYPOTENUSE OF A RIGHT - ANGLED TRIANGLE IS 5cm AND THE OTHER TWO SIDES DIFFER BY 1cm . FIND THE LENGTHS OF THE SIDES OF THE TRIANGLE.
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Answer:
answer is 4
Step-by-step explanation:
bcoz
given hypotenuse=5cm
let one side be=x
then other side will be=x-1
since sum of square of 2 sides=hypotenuse square
therefore, x²+(x-1)²=5²
x²+x²-2x+1=25
2x²-2x-24=0
2(x²-x-12) =0
x²-x-12=0
now,factorise.
x²-4x+3x-12=0
x(x-4)+3(x-4)=0
(x+3)(x-4)=0
since distance can't be negative
therefore,
x=4.[one side]
x-1=3[other side]
okay.. bye
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