Question

. The hypotenuse of a right triangle is 1 m less than twice the shortest side. If third side is 1 m more than the shortest side, find the sides of the triangle.

PLZZ ANSWER AS FAST AS POSSIBLE

Answer 1

Answer:

Let the shortest side of the triangle be 'x' m

hypotenuse=(2x-1)m

third side=(2x+1)m

By Pythagoras theorem,

(short side)²+(third side)²=(hypotenuse)²

(x)²+(2x+1)²=(2x-1)²

x²+(2x)²+(1)²+2(2x)(1)=(2x)²+(1)²-2(2x)(1)

(2x)² &(1)² are cancelled on both sides

x²+4x+4x=0

x²+8x=0

x(x+8)=0

x=0 and x+8=0

x=0 and x=-8

we should not get negative value

I think question is wrong.