Question

the hypotenuse of a right triangle is 1 metre more than the twice of the shortest side if the third side is 2 metre less than the hypotenuse find the sides of the triangle​

Answer 1

Step-by-step explanation:

sides are 8,15,17cm taking smallest side x

Answer 2

Answer:

I mistakenly took a side 2 . If you want you can delete . But yeah method will be same . And solution is right for same .

Let shortest side be x . then hypotenuse will be

twice of it plus 1 or 2x + 1 . Other side is 2 .

Now use Pythagoras

$(2x + 1) {}^{2} = {x}^{2} + {2}^{2} \\ 4 {x}^{2} + 1 + 4x = {x}^{2} + 4 \\ 3 {x}^{2} + 4x - 3 = 0 \\ x = \frac{ - 4 \pm \sqrt{16 + 4 \times 3 \times 3} }{2} \\ x = - 2 + \sqrt{13} \: \: ( \: side \: cant \: be \: negative)$

So hypotenuse = 2(-2+√13) + 1 =2√13 - 3