Question

The hypotenuse of a right triangle is 13 cm. If the difference of remaining two sides is
7 cm, find the remaining two sides.

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Answer 1

Answer:

12,5

Step-by-step explanation:

let one side be (x) and the other be(x-7)

H²=P²+B²

13²=x²+(x-7)²

169=x²+x²+49-14x

2x²-14x+49-169=0

2x²-14x-120=0

x²-7x-60=0

x²-12x+5x-60=0

x(x-12)+5(x-12)=0

(x+5)(x-12)=0

x+5=0

x=-5

x-12=0

x=12

so taking the value of x=12 we get

one side =12

other side =5