The hypotenuse of a right triangle is 20cm .If the difference between other two sides is 4cm .Find the length of each side
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Let first side be x
And second be x -4
Hypotenuse is 20cm
By pythagoras theorem,
20² = x² + (x-4)²
400 = x² +x²+16-8x
2x² - 8x - 384 = 0
(divide all by 2)
x² - 4x - 192 = 0
x² +12x - 16x -192 = 0
x(x+12)-16(x+12)=0
x = -12 , x = 16
Since x cannot be negative
x = 16
1st side = x = 16cm
2nd side = x-4 = 16-4 = 12cm
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