the hypotenuse of a right triangle is 26 cm long if one of the remaining two sides is 10 cm find the length of the other side
Answers
Answered by
187
Let the other side be x.
Then by Pythagoras Theorem,
26^2 = 10^2 + x^2
676 = 100 + x^2
676 - 100 = x^2
√576 = x
x = 24
Therefore, the third side of the triangle is 24cm.
Please mark as brainliest if it helps you...
Then by Pythagoras Theorem,
26^2 = 10^2 + x^2
676 = 100 + x^2
676 - 100 = x^2
√576 = x
x = 24
Therefore, the third side of the triangle is 24cm.
Please mark as brainliest if it helps you...
Answered by
53
Let ∆ ABC be right-angled at C.
Let AB=26 cm and BC=10 cm
Then, by pythagoras' theorem,
AB^2=BC^2+AC^2
=>AC^2= (AB^2-BC^2)
=(26^2-10^2)cm^2
=(676-100)cm^2
=576 cm^2
AC=√576 cm=24 cm
Let AB=26 cm and BC=10 cm
Then, by pythagoras' theorem,
AB^2=BC^2+AC^2
=>AC^2= (AB^2-BC^2)
=(26^2-10^2)cm^2
=(676-100)cm^2
=576 cm^2
AC=√576 cm=24 cm
Similar questions