Question

The hypotenuse of a right triangle is 3/2 metres and another side is 1/2m.Calculate the perimeter correct to a centimetre.​

Answer 1

$\bf\underline{\underline{\blue{Answer:-}}}$

From (1), a=17−b

Substitute value of a in equation (2) we get,

−12b−5b+60=0 ...... factorized above equation

⟹ b(b−12)−5(b−12)=0

⟹ (b−12)(b−5)=0

∴ b=12 or b=5

If b=12 then a=17−12=5

If b=5 then a=17−5=12.

Hence the length of other two sides are 12,5.

Answer 2

Answer:

$\fbox \pink {A}\fbox \blue {n} \fbox \purple {s} \fbox \green{w} \fbox \red {e} \fbox \orange {r}$

Given,

From (1), a=17−b

Substitute value of a in equation (2) we get,

−12b−5b+60=0 ...... factorized above equation

⟹ b(b−12)−5(b−12)=0

⟹ (b−12)(b−5)=0

∴ b=12 or b=5

If b=12 then a=17−12=5

If b=5 then a=17−5=12.

Hence the length of other two sides are 1,2,5.

$\orange{\tt{ Papa Di Sherni ♡~}}$