The hypotenuse of an isosceles right triangle whose one side is 4 under root 2 cm is
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let ABC be the isosceles triange
let AC be the hypo
as given it is isosceles triangle 2 sides are equal
therefore AB=BC
by pythagoras theorem
AC^2=AB^2+BC^2
AC^2=(4root2)^2 +(4root2)^2
AC^2=16(2)+16(2)
AC^2=32+32
AC^2=64
AC=root64
AC=8cm
therefore the hypotenus of isosceles triangle is 8 cm
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