the identical charges each of 1.0µc are placed at the corners of an equilateral triangle of side 10cm. the electric field intensity at the centre of triangle is
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he force at A due to charge +Q at C is outward from C and the force at A due to charge -Q at B is towards B as shown in figure. So the resultant is parallel to BC. Thus there will no force in a direction normal to BC.
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