the image of an object as formed by a lens is of magnification -1.If distance between the object and image is 60cm,then find the focal length of the lens? if the object is moved 20cm towards the lens , where would the image be formed? draw a ray diagram in support of your answer
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Answer:
f= 15cm
Image will be formed at 6cm on left side of the lens.
Explanation:
Since image is not magnified, the object is placed at 2f. So, u=v i.e. object distance = Image distance. (-1= v/u. )
-ve sign indicates that the lens is a concave lens.
Given: v+u=60cm.
Substitue u=v.
u= 30cm.
Now we also know that the obejct is at 2f
so , 2f= u
Therefore f= 15cm
Now, new object distance= u2 = u -20 cm.
= 30 -20
=10 cm.
Using lens formula,
1/f=1v- 1/u.
f= - 15cm for concave lens.
u= - 10 cm
Find v.
v comes out to be -6cm. Which means it is on the same side as the obejct.
Accordingly draw the ray diagram.
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