Question

the image of an object formed by a mirror is real inverted and is of magnification -1. if the image is at the distance of 30 cm from the mirror as the object placed find the position of the object if the object is now moved 20cm towards the mirror what is the nature of the image obtained. justify for your answer with the help of a diagram

Answer 1

Negative magnification :- Negative magnification indicates that both object and image formed have different orientations. If the object is erect then the image formed by a spherical mirror (concave or convex) is inverted. An inverted image is always real. Thus, negative magnification means that the image formed by a spherical mirror is real. Positive magnification :- It means that both the object and the image formed by a spherical mirror (concave or convex) are erect (I.e., upright). An erect image is always virtual. Thus, positive magnification indicates that the image formed by a spherical mirror is virtual. Linear magnification (m) :- linear magnification produced by a mirror is the ratio of the size of the image formed (denoted by h') to the ratio of the size of the object

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Answer 2

Answer:

+ 30 cm

Explanation:

Given :

Magnification = - 1

Image distance = 30 cm

We know

m = - v / u

- 1 = 30 / u

u = - 30 cm

Now we have ,

1 / f = 1 / v + 1 / u

1 /  f = 1 / - 30 - 1 / 30

f = - 15 cm

When object moved 20 cm

u' = - 30 + 20 = - 10 cm

We have f = - 15 cm

We have to find new image distance v'

Again ,

1 / f = 1 / v' + 1 / u'

- 1 / 15 = 1 / v' - 1 / 10

1 / v' = 1 / 30

v' = 30.

Nature of image as :

Virtual

Erect

Magnified.