Physics, asked by Aditi3981, 1 year ago

the image of an object formed by a mirror is real, inverted and is magnification -1. if the image is at the distance of 30 Cm from the mirror,where is the object placed? find the position of the image if the object is now moved 20 cm towards the mirror. what is the nature of the image formed?


Aditi3981: will you help to answer that question

Answers

Answered by BendingReality
0

Answer:

+ 30 cm

Explanation:

Given :

Magnification = - 1

Image distance = 30 cm

We know

m = - v / u

- 1 = 30 / u

u = - 30 cm

Now we have ,

1 / f = 1 / v + 1 / u

1 /  f = 1 / - 30 - 1 / 30

f = - 15 cm

When object moved 20 cm

u' = - 30 + 20 = - 10 cm

We have f = - 15 cm

We have to find new image distance v'

Again ,

1 / f = 1 / v' + 1 / u'

- 1 / 15 = 1 / v' - 1 / 10

1 / v' = 1 / 30

v' = 30.

Nature of image as :

Virtual

Erect

Magnified.

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