Question

The image of an object, formed by a plano-convex lens at a distance of 8m behind the lens, is real and is one third the size of the object. The wavelength of light inside the lens is 2/3 times the wavelength in free space. The radius of the curved surface of the lens is

Answer 1

Answer:

ANSWER

Since the wavelength of light becomes

3

2

times of the wavelength in free space, the refractive index of the material of lens is

2

3

=1.5

Consider refraction from first surface,

v

1

1.5

−

u

1

=

R

1.5−1

For refraction from second surface,

v

2

1

−

v

1

1.5

=

∞

1−1.5

Hence,

v

2

1

−

u

1

=

R

0.5

Magnification of the lens is given by M

1

×M

2

=

u

v

1

×

v

1

v

2

=

u

v

2

=

3

−1

(negative since image is real)

It is given that v

2

=8m

⟹u=−24m

Hence, R=3m

Explanation:

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Answer 2

Answer:

Explanation:

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