the image of an object placed at 24 cm in front of a lens is obtained on a screen at a distance of 72 cm from its calculate the focal length of the lens what would be the height of the image if the object is 2 centimetre in high also find the power of lens
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Answer:
u = - 24 cm
f = 8 cm ...(focal length of convex lens)
1 over f equals space 1 over v minus 1 over u
1 over v space equals space 1 over f plus 1 over u
1 over v equals 1 over 8 plus fraction numerator 1 over denominator negative 24 end fraction equals 1 over 12
v space equals space 12 space c m space
T h u s space i m a g e space i s space f o r m e d space a t space a space d i s tan c e space o f space 12 space c m space b e h i n d space t h e space l e n s.
The image is formed to the right so, the image formed will real and inverted.
Magnification of image is given by,
m = v/u = 12/-24 = - 0.5
This implies that magnification is -0.5 which means image is diminished.
Explanation:
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