Question

The image of the object formed by a mirror is real inverted and is of magnification -1 if the image is at distance of 30 cm from the mirror where is the object placed find the position of the image if the object is not move 20cm towards the mirror what is the nature of the image of 10 justify your answer with the help of ray diagram

Answer 1

Could you please send a picture of this question and send us....
It would be really helpful

Answer 2

Answer:

+ 30 cm

Explanation:

Given :

Magnification = - 1

Image distance = 30 cm

We know

m = - v / u

- 1 = 30 / u

u = - 30 cm

Now we have ,

1 / f = 1 / v + 1 / u

1 /  f = 1 / - 30 - 1 / 30

f = - 15 cm

When object moved 20 cm

u' = - 30 + 20 = - 10 cm

We have f = - 15 cm

We have to find new image distance v'

Again ,

1 / f = 1 / v' + 1 / u'

- 1 / 15 = 1 / v' - 1 / 10

1 / v' = 1 / 30

v' = 30.

Nature of image as :

Virtual

Erect

Magnified.