Question

the impedance of a circuit containing a resistance of 1ohm and an inductance of 0.1 H in series for ac of 50 H is approximately​

Answer 1

Given:

The resistance of the circuit is  R= 1 ohm

The inductance is L=0.1 H

The frequency is  50 Hz

To find:

The impedance of the circuit.

Solution:

The formula of impedance is

Z=$\sqrt{} R^{2}+X^{2}$

Where X= 2πvL

Putting the above values

X=2×3.14×50×0.1

X=31.4  ohm

Now Put all the values in the above formula

Z=$\sqrt{} 1^{2} +(31.4)^{2}$

Z=31.41

So the impedance of the circuit is 31.41 ohm

Answer 2

Explanation:

hope this will help you