Question

The Incircle of a traingle abc touches the sides BC, CA and AB at D, E and F respectively. If AB is equal to AC, Prove that BD is equal to CD

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

GIVEN THAT-The In circle of a traingle ABC touches the sides BC, CA and AB at D, E and F respectively

AB=AC-------(i)

Now,Because we know that an external  point to a circle,the lines are equal

i.e.,tangents

SO,AF=AE-----(ii)

    BF=BD-----(iii)

     DC=EC----(iv)

NOW BECAUSE,

AB=AC   HENCE,AF=BF and so AE=EC

SO BD=CE  (PROVED)