the incircle of triangle ABC toches the sides BC,CA,AND AB at D,E,AND F respectively .if AB =AC,prove that BD=CD
Answers
Answered by
395
Hope it helps you.
Also pls do mark it as brainliest.
Thank you.
And wish you a very Happy New Year.
Also pls do mark it as brainliest.
Thank you.
And wish you a very Happy New Year.
Attachments:
YASH3100:
Pls add it as brainliest brother
Answered by
93
Given: AB = AC. ........(1)
To Prove: BD = CD.
Proof: BD = BF ........(2)[Tangents drawn
AE = AF. .........(3)from external
CE = CD .........(4)point of a circle
are equal]
now, AB = AC
AF + BF = AE + CE (AF = AE from - 1)
SO, BF = CE
( BF = BD & CE = CD )
BD = CD
HENCE PROVED
To Prove: BD = CD.
Proof: BD = BF ........(2)[Tangents drawn
AE = AF. .........(3)from external
CE = CD .........(4)point of a circle
are equal]
now, AB = AC
AF + BF = AE + CE (AF = AE from - 1)
SO, BF = CE
( BF = BD & CE = CD )
BD = CD
HENCE PROVED
Similar questions