Question

the incircle of triangle Abc touches the sides bc .ca and ab at d e and f respectively show that af+bd+ce=1/2 the perimeter of triangle abc =ae+bf+cd

Answer 1

We have AF=AE
CD=CE
BF=BD because tangents drawn to the same circle
We'll add them all
AF+CD+BF=AE+CE+BD
substitute the above equations on the RHS
So AF+CD+BF=AF+CE+BD
For the perimeter part u just need to again substitute the values

Answer 2

Hope this helps u :-)