Math, asked by shivanshibhardwj, 1 year ago

the incircle of triangle Abc touches the sides bc .ca and ab at d e and f respectively show that af+bd+ce=1/2 the perimeter of triangle abc =ae+bf+cd

Answers

Answered by brainly012
128
We have AF=AE
CD=CE
BF=BD because tangents drawn to the same circle
We'll add them all
AF+CD+BF=AE+CE+BD
substitute the above equations on the RHS
So AF+CD+BF=AF+CE+BD
For the perimeter part u just need to again substitute the values
Answered by Himanshukajaria
321
Hope this helps u :-)
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