Question

The inclination of line x-√3y+1=0 with positive x-axis is....

Answer 1

Given equation 1x-root3y+1=0
Compare given equation with ax+by+c=0
a=1,b= - root3, c=1
Inclination =slope= m= tan θ=-a/b
Tanθ=-(1/-root3)
Tanθ= 1/root3
Tanθ=tan 30
θ=30 degrees