Question

The increase in length of a wire on stretching is 0.6% Ir its poison ratio is 0.2, then the percentage decrease in the diameter is
(A) 0.002
(B) 0.001
(C) 0.003
(D) 0.005​

Answer 1

Answer:

Suppose, D be the diameter of the wire Poissons ratio,

σ=

longitudinalstrain

lateralstrain

σ=

L

ΔL

D

ΔD

L

ΔL

=0.025

σ=0.004

σ=

40

1

D

ΔD

D

ΔD

=

40

1

×0.4=0.01

Answer 2

that's not the reason

reason is something else