The increasing order of stability of the following free radicals
is
• • • •
(a) (C₆H₅)₂ CH < (C₆H₅)₃ C < (CH₃)₃C < (CH₃)₂ CH
• • • •
(b) (CH₃)₂ CH < (CH₃)₃ C < (C₆H₅)₂ C H < (C₆H₅)₃C
• • • •
(c) (CH₃)₂ CH < (CH₃)₃ C < (C₆H₅)₂ CH < (C₆H₅)₃C
• • • •
(d) (C₆H₅)₃ C < (C₆H₅)₂ C H < (CH₃)₃ C < (CH₃)₂ CH
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number C is the answer please mark me as a Brainleis
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Option (c) i.e. (CH₃)₂ CH < (CH₃)₃ C < (C₆H₅)₂ CH < (C₆H₅)₃C is correct for the given question.
- Free radicals are stabilized by the alpha (α) hydrogen. More the number of alpha (α) hydrogen more will be hyperconjugation and hence more will be the radical stabilization resonance.
- Hyperconjugation refers to the stabilising interaction which happens because of the interaction of the electrons in the σ-bond (usually C-H or C-C ) with anadjacent empty or partially filled p-orbital or a π-orbital to give an extended molecular orbital that increases the stability of the system.
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