Question

The initial position of an object at rest is given by 3î-8j.it moves with constant acceleration and reaches to the position 2î+4j after 4 sec .what is its acceleration

Answer 1

Displacement= final position-initial position

Thus displacement
= (2î+4j) - (3î-8j)
= -î + 12j

Magnitude of displacement traveled
= root 1^2+12^2
= root145
=12.04 m

Now time= 4 sec
Initial velocity= 0
a=?

using s= ut+1/2 at^2
12.04= 1/2 x 16a
a= 12.04/8
a= 1.505 m/s^2

Answer 2

This is what the right solution matches with option.