Question

The initial velocity of a body moving along a straight line is 7m/s it has uniform accelaration of 4m/s2. The distance coverd by the body in the 5th second of its motion is

Answer 1

V=7+4(4)(as at the beginning of 5th sec,it has completed 4 sec of its journey)

V=23m/s

2)s=ut+1/2a(t)(t)

During 5th sec of its journey,it takes 1sec.

T=1

S=23(1)+1/2 (4)(1)(1)

S=25m

pls mark brainliest