The initial velocity of a particle is calculated as for which displacement x of a particle at time t along a straight line is given by(all in SI units)
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WKT, 3
rd
equation of Kinematics is given by v
2
=u
2
+2aS−−(1),
Where, u= initial velocity
v= final velocity , a= acceleration and S= Distance
Given , v=
3x+16
Squaring both side we get, v
2
=3x+16⇒v
2
−16=3x⇒v
2
−4
2
=3x−−(2)
Now, Comparing equation (1) and (2) , we get
u=4units and 2a=3⇒a=1.5units
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