Question

the initial velocity of a particle is u=0 at t=0 and x=0 and its acceleration a =k.x then what is relation between its velocity and position(x)

Answer 1

a=kx

u=0

v=v

u=0

t=0

also

a=dv/dt

dv/dt=kx

dv=kxdt

integrating

$\int\limits^v_u\, dv= \int\limits^t_0 {kx} \, dt$

v-u=kxt

v=kxt

hope this helps