Question

the initial velocity of a particle moving along a straight line is 10m/s and it's retardation 2 m/s2. The distance moved by the body in 5th second of its motion is​

Answer 1

Given:-

• Initial velocity (u) = 10m/s

• Retardation (a) = 2m/s²

• time (n) = 5th second

To Find:-

• Distance moved by the body in 5th second

Solution:-

By using this formula

→ Sn = u +a/2(2n-1)

Substitute the value we get

→ S5 = 10 + (-2)/2 (2×5 -1)

→ S5 = 10 - 1(10-1)

→ S5 = 10 -1(9)

→ S5 = 10 -9

→ S5 = 1m

∴ The distance covered by the body in 5th second is 1 metre.