Physics, asked by SaiRaghavender477, 8 months ago

The initial velocity of a projectile is3i+4jm/s where I along the ground j is along the vertical. The maximum height of the projectile is(use h=10m/s2

Answers

Answered by kvinesh571
0

Answer:

H=Vo2/2g

H=(5)2/2(10)

H=1.25

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