Question

The initial velocity of a train which is stopped in 20 seconds by applying brakes
with retardation of 1.5 metre per second square is​

Answer 1

$\huge</p><p>\pink{\mid{\underline{\overline{\tt Answer : }} \mid}}$

Final velocity (v)= 0m (as it comes to rest)

Acceleration (a)= -1.5m/s^2

Time (t)=20s

Let initial velocity be u

Using acceleration formula

a=(v-u)/t

-1.5 = (0-u)/20

-30 = -u

u=30

So, the initial velocity was 30m/s.

$<marquee> mark me as brainlist ok$