Question

The initial velocity of an object is ū=5i+10j m/s. Its constant
acceleration is a = 2i +3j m/s². What will be its velocity after 5s?
A​

Answer 1

Answer:

The velocity (v) after 5 seconds will be 15 i + 25 j m/s

Given:

1. Initial velocity (u) = 5 i + 10 j m/s

2. Acceleration (a) = 2 i + 3 j m/s²

3. Time taken (t) = 5 sec.

Explanation:

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From the first kinematic equation we know,

⇒ v = u + a t

Substituting the values,

⇒ v = 5 i + 10 j + ( 2 i + 3 j ) × 5

⇒ v = 5 i + 10 j + 10 i + 15 j

⇒ v = ( 10 + 5 ) i + ( 10 + 15 ) j

⇒ v = 15 i + 25 j

⇒ v = 15 i + 25 j m/s

∴ The velocity (v) after 5 seconds will be 15 i + 25 j m/s.

Note:

• Symbols have their usual meanings.

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Some Formulas:

⇒ v² - u² = 2 a s

⇒ S_n = u + a / 2 ( 2 n - 1 )

⇒ S = u t + 1 / 2 a t²

⇒ | a | = √ (a_x)² + (a_y)²

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Answer 2

$\huge\underline\mathtt\red{Answer:-}$

the velocity after 5 seconds will be 15 i+ 25j m/s.