Question

The inner and outer circumference of a circular ring is 44 cm and 88 cm respectively. Find the width of the ring

Answer 1

circumference of a circle = 2$\pi$r
circumference of inner circle  = 2 $\pi$r
44=2$\pi$r
r=$\frac{44}{2 \pi }$
r=$\frac{22}{ \pi }$

circumference of outer circle = 2$\pi$r
88=2$\pi$r
r=$\frac{44}{ \pi }$
 width = radius of outer circle - readius of inner circle
=> $\frac{44}{ \pi } - \frac{22}{ \pi }$
=>$\frac{22}{ \pi }$
=>22 x $\frac{7}{22}$
=7 cm

Answer 2

Answer:

7 cm

Step-by-step explanation:

Given : The inner and outer circumference of a circular ring is 44 cm and 88 cm respectively.

To Find:  Find the width of the ring

Solution :

Circumference of a circle = $2\pi r$

So, Circumference of outer circle 88 cm= $2\pi r$

⇒ $88=2\pi r$

⇒44/π =r

Thus radius of outer circle is 44/π cm

circumference of inner circle = 2πr

44 = 2πr

22/π =r

Thus the radius of inner circle is 22/π

 Since width = radius of outer circle - radius of inner circle

=> $\frac{44}{\pi} -\frac{22}{\pi }$

=> $\frac{22}{\pi}$

use π =22/7

=> $22*\frac{7}{22}$

Thus the width of ring =7 cm