Question

The inner circumference of a circular field is 704 m. A road 7 m wide is constructed on the outside. Find the area of the path.

Answer 1

Answer:

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Answer 2

The area of path is 5082 sq.m.

Step-by-step explanation:

Circumference of circular field = 2 \pi r

We are given that The inner circumference of a circular field is 704 m.

So, $2 \pi r = 704$

$2 \times \frac{22}{7} \times r = 704$

$r=\frac{704 \times 7}{2 \times 22}$

r=112 m

A road 7 m wide is constructed on the outside.

Outer radius R = 112+7=119 m

Area of path = Outer area - Inner area

Area of path =$\pi R^2 - \pi r^2$

Area of path = $\frac{22}{7}(119^2-112^2)$

Area of path =$5082 m^2$

Hence The area of path is 5082 sq.m.

#Learn more:

A circular pond is surrounded by a 2 m wide circular path. If outer circumference of circular path is 44 m, find the inner circumference of the circular path. Also find area of the path

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