The inner circumference of a circular track is 121 m. The track is 3.5 m wide. find the area of the track.
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Answer:
So
circumference is give that is = 121 m
It is also equal to 2×pi×r
Now width =3.5 m
2×pi×r =121 given
2×22/7× r = 121
r =121 ×7/2×22
r =19.25
INNER AREA OF TRACK =PI×R^2
=22/7×19.25^2
=22/7×370.5625
=105.875 m²
NOW
R= 19.25+3.5
=22.75
FULL AREA =PI ×R^2
=22/7 ×22.75^2
22/7 ×517.5625
=1626.625 m²
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