the inner circumference of a circular track is 242m. the track is uniformaly 7m wide. find the area of the track.
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Inner Circumference = 242 m
=> 2 pi r = 242
=> 2 × 22 × r / 7 = 242
=> r = 242 × 7 / 44
=> r = 11 × 7 / 2
=> r = 77/2
=> r = 38.5 m
Inner Radius = 38.5 m
Outer Radius = Inner Radius + Width of track
Outer Radius = 38.5 + 7 = 45.5 m
Area of track = Outer Area - Inner Area
= pi R^2 - pi r^2
= pi ( R^2 - r^2)
= pi ( R +r) (R - r)
= pi × 84 × 7
= 22 × 84 × 7 / 7
= 22 × 84
= 1848 m^2
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Right answer is 1848m square
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