Question

the inner circumference of a circular track is 264 m and the width of the track is 7 m . find
1)the radius of the inner track
2)the radius of the outer circumference
3)the length of the outer circumference
4)the cost of fencing the outer circumference at the rate of $50 per meter​

Answer 1

Answer:

1:42m

2:49m

3:308m

4:$15400

Step-by-step explanation:

let the radius of the circle be r

GIVEN:inner circumference=264m

             width of track=7m

2πr =264

1:πr=$\frac{264}{2}$

r=132*7/22

r=66*7/11

r=6*7

r=42m

therefore the radius of the inner circle is 42m

2:let the radius of the outer circle be x

   x =(radius of inner circle+width of track)

   x=42+7

   x=49

   therefore the radius of the outer circle is 49m

  3:outer circumference =2π(radius of outer circle)

      outer circumference = 2*22/7*49

      outer circumference = 2*22*7

      outer circumference = 2*154

      outer circumference = 308m

      therefore the outer circumference of the circle is 308m

    4:cost of fencing the outer circumference at the rate of $50/m=

       circumference of outer circle*cost of fencing/m

       =308*50

       =$15400

       therefore the cost of fencing the outer circumference of the circle at

       the rate of $ 50/m is $15400