Question

The inner circumference of a hollow cylindrical pipe is 4.5 outer circumference is a 4.6 metre find the cost of painting what its inner and Outer side @ rupees 20 per metre square if it 8 metre tall

Answer 1

Answer:

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Given,

For the hollow cylindrical pipe ,

Inner circumference = 44 dm = 4.4 m

Outer circumference = 45 dm = 4.5 m

Height of the cylindrical pipe = 3.5 m

•°• Inner curved surface area = Inner circumference × Height

= 4.5 m × 3.5 m

= 15.4 sq.m

And,

Outer curved surface area = Outer circumference × Height

= 4.5 m × 3.5 m

= 15.75 sq.m

•°• Total surface area of the pipe that is to be painted = Inner curved surface area + Outer curved surface area

= ( 15.4 + 15.75 ) sq.m

= 31.15 sq.m

Now,

Cost of painting per sq.m = Rs. 2

•°• Cost of painting 31.15 sq.m = Rs. ( 2 × 31.15 )

= Rs. 62.30

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