The inner circumference of a hollow cylindrical pipe is 4.5 and outer circumference is 4.6 . Find the cost Of painting both it inner or outer Side at the rate of 20 per square meter
If it 8 m tall
Answers
The cost of painting both its inner or outer side at the rate of 20 per square meter is Rs. 1454.
Explanation:
The height of the cylinder is given as = 8 m
Step 1:
The inner circumference of the hollow cylinder pipe = 4.5 m
Let the inner radius of the base of the hollow cylinder be “r” m.
∴ 2πr = 4.5
⇒ r = [4.5*7] / [2*22]
⇒ r = 0.715 m
∴ Area of the inner side of the hollow cylinder to be painted is given by,
= 2πrh
= 2 * 22/7 * 0.715 * 8
= 35.95 m²…. (i)
Step 2:
The outer circumference of the hollow cylinder pipe = 4.6 m
Let the outer radius of the base of the hollow cylinder be “R” m.
∴ 2πR = 4.6
⇒ R = [4.6*7] / [2*22]
⇒ R = 0.731 m
∴ Area of the outer side of the hollow cylinder to be painted is given by,
= 2πRh
= 2 * 22/7 * 0.731 * 8
= 36.75 m² ….. (ii)
Step 3:
Now, from (i) & (ii), we get
The total area of the hollow cylinder to be painted
= 35.95 + 36.75
= 72.7 m²
The cost of painting per meter square is given as = Rs. 20
Thus,
The cost of painting both the inner and outer side of the hollow cylinder is,
= 72.7 m² * Rs. 20
= Rs. 1454
---------------------------------------------------------------------------------------
Also View:
A hollow cylinder of internal radius 3 cm external radius 4 cm and height 10 cm is to be painted completely what will be the cost of painting if the rate of painting is rupees 2 per cm² .
https://brainly.in/question/7534364
A hollow cylindrical pipe has inner circumference 44 dm and outer 45 dm. Find the cost of painting it from both sides at Rs. 2 per m², if its length is 3.5 m.
https://brainly.in/question/50183