Question

The inner diameter of a 15m deep circular well is 4.2m. Find the cost of plastering it's corner covered surface at the rate of 50 rupees per meter sqare​

Answer 1

Answer:

I think, Rs.92400

Step-by-step explanation:

c.s.a of cylinder = 2πrh

=

$2( \frac{22}{7})( \frac{4.2}{2})(15) \\ = \frac{12936}{70} \\ = 1848$

= 1848 m^2 is inner area of well

now ,rate is

= 1848 ×50

= rs.92,400, I think it's correct.

hope helps

Happy New year

Answer 2

Answer:

inner cover surface is = 9900 rs.

Step-by-step explanation:

inner inner cover surface is equal to 2 Pi r h

d=2r = 4.2m

r= 2.1 m

h= 15

2 Pi r h = 2×(22/7)×2.1×15

=198sq. m

198×50

= 9900