Question

The inner diameter of a cylindrical wooden pipe is 24 cm. and its outer diameter is 28 cm. the length of wooden pipe is 35 cm. find the mass of the pipe, if cu cm of wood has a man of 0.6 g.

Answer 1

☆Hello friend☆

Respective, radius = 28 cm/2 and 24 cm/2

= 14 cm and 12 cm

Volume of that hollow pipe (Here r1 is 14 cm and r2 is 12 cm)

$= \pi {r1}^{2} h - \pi {r2}^{2} h$

= 22/7 × 35 cm( 14^2 -12^2) cm^2

= 22 × 5cm( 14-12)(14+12)cm^2

= 110 cm × 2 cm × 26 cm

=5720 cm^3

Its weight = 5720 × 0.6 g

= 3432 gram

Hope it helps☺