Question

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The inner diameter of a iron pipe is 24 cm and its outer diameter is 28 cm. The length
Find the mass of the pipe, if 1 cm of iron has mass 12 g.
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Answer 1

Complete Question :

The inner diameter of a iron pipe is 24 cm and its outer diameter is 28 cm. The length of Pipe is 35 cm. Find the mass of the pipe, if 1 cm³ of iron has mass 12 g.

AnswEr :

• Inner Diameter of Pipe = 24 cm
• Inner Radius of Pipe ( r ) = 12 cm
• Outer Diameter of Pipe = 28 cm
• Outer Radius of Pipe ( R ) = 14 cm

So we can see that the thickness of Pipe will be 2 cm i.e. (14 - 12) cm.

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• Calculation of Volume of Pipe :

$\longrightarrow \tt Volume = Outer \: Volume - Inner\:Volume \\ \\\longrightarrow \tt Volume = \pi{(R)}^{2}h - \pi {(r)}^{2}h \\ \\\longrightarrow \tt Volume = \pi h{(R}^{2} - {r}^{2}) \\ \\\longrightarrow \tt Volume = \dfrac{22}{ \cancel7} \times \cancel{35} \times(14 + 12) \times(14 - 12) \\ \\\longrightarrow \tt Volume = 22 \times 5 \times26 \times2 \\ \\\longrightarrow \blue{ \tt Volume = 5720\:{cm}^{3} }$

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• M A S S ⠀O F ⠀P I P E :

⇒ Mass of Pipe = Volume × Mass of Unit

⇒ Mass of Pipe = 5720 cm³ × 12 g/cm³

⇒ Mass of Pipe = 68640 gm or, 68.64 Kg

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∴ Mass of Cylindrical Pipe is 68.64 Kg

#answerwithquality #BAL

Answer 2

Answer:

• Find the radius:

r1 = 28 ÷ 2 = 14 cm

r2 = 24 ÷ 2 = 12 cm

• Find the volume of the wood:

=> Volume = πh(r1² - r2²)

=> Volume = π(35)(14² - 12²)

=> Volume = 5720 cm³

• Find the mass of the pipe:

1 cm³ = 12g

5720 cm³ = 12 x 5720 = 68.64 kg

★ Mass of Pipe is 68.64 Kg